2x^-5/3y^0

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Solution for 2x^-5/3y^0 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

y^0*((2*x^-5)/3) = 0

(2*x^-5)/3 = 0

2/3*x^-5 = 0 // : 2/3

x^-5 = 0

x należy do O

x belongs to the empty set

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